the actual number is 34+34*10+34^2 = 1530 bits
Cadence has 34 bits. Luna has ten times that, 340 bits. Celestia has the same amount as bits as Luna does, squared ("same number of bits Luna has, multiplied by the number of bits Luna has"). 340^2 = 115600. Total bit count is then 115974. But then again, Celestia has probably had a lot, lot more time to gather all these bits...
two trains, Train A and Train B,which simultaneously depart Station A and Station B. Station A and Station B are 252.5 miles apart from each other. Train A is moving at 124.7mph towards Station B, and Train B is moving at 253.5mph towards Station A. If both trains departed at 10:00AM and it is now 10:08, how much longer until both trains pass each other?
d = 406.3km, v_a = 200.6km/h, v_b = 407,9km/h.
t = d / (v_a + v_ b) = 0.668h, or approximately 40 minutes. This then leaves 32 minutes of travel time before they meet.
Having bought tickets to Saddle Arabia, the three Princesses realize they'll need more bits to return to Equestria, or face a long journey home. Work is available for all three in Saddle Arabia paying 35 bits per hour doing admin work. The journey home would take 45 hours of flying and walking to get back to Canterlot, which choice gets the Princesses home faster? Continue the assumption that tickets cost 1039 bits.
In order to earn enough to get home, they would need 3117 bits in total. Assuming initial money to be 657, since the actual sum would be significantly more, based on the first question. This means they need 2460, which implies that they have to work for 23.4 hours each. Without information on how fast the airship is, this question can't be fully answered. If the airship completes the trip in less than 21.6 hours, it would be faster to work, otherwise manual flight is faster.
...
Later, when got back to Canterlot they wanted to play a game where they could chose a sequence of three numbers from a pool of five. Getting all three numbers correct would give them a reward. Assuming they chose a sequence of numbers each (total three unique sequences), what are the odds that at least one of them won something?
Edited by Hepolite, 22 February 2016 - 02:29 AM.