"Untitled"
By gando (https://pastebin.com/u/gando)

URL: https://pastebin.com/AHGNerLQ
Created on: Friday 6th of May 2011 03:59:45 PM CDT
Retrieved on: Saturday 31 of October 2020 07:59:08 AM UTC


import re
from urllib import urlopen
  #init the lists
uniqueBanList = []
totalBanList = []
tempList = []
url = 'http://74.63.239.234/banlist.txt'
import itertools
import operator
import os
import time
permaBannedList = re.findall(r'(\bSTEAM_[0-1]:[0-1]:\d+\b) 0 .*', urlopen('http://74.63.239.234/banlist.txt').read())
  # find all people permanently banned and add them to a list


def most_common(L):
  # get an iterable of (item, iterable) pairs
  SL = sorted((x, i) for i, x in enumerate(L))
  # print 'SL:', SL
  groups = itertools.groupby(SL, key=operator.itemgetter(0))
  # auxiliary function to get "quality" for an item
  def _auxfun(g):
    item, iterable = g
      # set these variables to the input to _auxfun()
    count = 0
      # reset the count variable for each person
    five = 5
      # yes, this was unneccessary, I know
    min_index = len(L)
    for _, where in iterable:
      count += 1
        # for each ban found, add one to the count we're keeping
      min_index = min(min_index, where)
      if _ in permaBannedList:
          # if the person we're checking is permabanned, say so damnit
        permabanned = 'yes'
      else:
          # but we want to make sure these motherfuckers with a shitton of bans
          # and no perma get caught
          # so if they aren't permabanned, make sure that it says they're not permabanned
        permabanned = 'no'
    if count >= five:
      #if they have more than five bans
        tempList.append('%r has been banned %r times. Permabanned: %r.' % (item, count, permabanned)        
        open('banlist_mostbanned'+time.strftime('_%I-%M%p_%m_%d_%y')+'.txt', 'a+').write('%r has been banned %r times. Permabanned: %r.\n' % (item, count, permabanned))
    return count, -min_index
  # pick the highest-count/earliest item
  return max(groups, key=_auxfun)[]

# a function for finding all of the occurences of a regex match
def num_groups(regex, url):
    webpage = urlopen(url).read()
    m = re.findall(regex, webpage)
    return m

if __name__ == "__main__":
   for i in num_groups(r'(\bSTEAM_[0-1]:[0-1]:\d+\b).*', url):
                          # this regex finds the first SteamID on a line
                          # and then moves to the next line
        totalBanList.append(i)
                          # when we find a match, add it to the list
        if i not in uniqueBanList: uniqueBanList.append(i)
                        # if there is a new SteamID that isn't in the
                        # unique ID list, add it to the unique ID list
print "There have been "+str(len(totalBanList))+ " total bans and "+str(len(uniqueBanList))+' unique people banned since the beginning of time on Noobonic Plague.\nThere have also been '+str(len(permaBannedList))+' permanent bans.'
yes = input(r"Do you want to see the list of most-banned people? 1 for yes, 0 for no. > ")
if yes == 1:
        print most_common(totalBanList)
        c = raw_input("Press enter to close the program.")